Y=-0.06x^2+5

Solution for Y=-0.06x^2+5 equation:

=-0.06Y^2+5

We move all terms to the left:

-(-0.06Y^2+5)=0

We get rid of parentheses

0.06Y^2-5=0

a = 0.06; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·0.06·(-5)
Δ = 1.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.2}}{2*0.06}=\frac{0-\sqrt{1.2}}{0.12}
=-\frac{\sqrt{}}{0.12}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.2}}{2*0.06}=\frac{0+\sqrt{1.2}}{0.12}
=\frac{\sqrt{}}{0.12}
$